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Question
Q240) In hydrogen atom, energy of first excited state is –3.4 eV. Then find out KE of same orbit of hydrogen atom



SOLUTION

K= −TotalEnergy(E)=3.4eV
Negative kinetic energy equals half the potential energy (−K = ½U).
Potential energy equals twice the total energy (U = 2E).
Total energy equals negative kinetic energy (E = −K).
Twice the kinetic energy plus the potential energy equals zero (2K + U = 0).
This is a key relationship for a larger problem in orbital mechanics known as the virial theorem.
Answer:(a)