Question

Q275) The uncertainty in momentum of an electron is 1 × 10^{–5} kg-m/s. The uncertainty in its position will be

(h = 6.62 × 10^{–34} kg-m^{2}/s)

Q275) The uncertainty in momentum of an electron is 1 × 10

(h = 6.62 × 10

SOLUTION

Use equation Δx × Δp = h/4π

Answer:(a)