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Q304) the ratio of the difference in energy between the first and the second Bohr orbit to that between the second and the third Bohr orbit is [ NCERT1980]


Energy of nth orbit ∝ 1/ n2 Thus E1=C/(1)
second orbit E2=C/(2)2=C/(4)
third orbit energy E3=C/(3)2=C/(9)
Difference E1 - E2=C (3/4)
Difference E2 - E3=C (5/36)
Thus ratio=3/4 ÷ 5/36=27/5
Answer: (d)