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Question
Q366) Pick out the isoelectronic structures from the following
I) CH3+
II) H3O+
III) NH3
IV) CH3-
[ IIT 1993




SOLUTION

Number of electrons in each case
CH3+=6 + 3 -1=8
H3O+=3 + 8 -1=10
NH3=7 + 3=10
CH3-=6 + 3 +1=10

Answer: (d)