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Question Q131) Volume occupied by one molecule of water (density = 1 g cm–3) is [AIPMT (Prelims)-2008] Solution



SOLUTION

As density =1g/cc
55.5 moles of water occupy 1000 mL volume
55.5×6.023×1023 molecules = 1000 mL Volume
1 molecule = 0.00299×10-20 L Volume
∴ Volume of 1 molecule = 3×10-23 cm3
Answer : (d)