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Question Q133) When 22.4 litres of H2(g) is mixed with 11.2 litres of Cl2(g), each at STP, the moles of HCl(g) formed is equal to [AIPMT-2014]


Reaction is
H2+ Cl2 → 2HCl
One of each H2 and C2 produce 2 moles of HCl
22.4 L of H2= 1 mole
11.2 Lof Cl2 = 0.5 mole
As Cl2 is only 0.5 mole
∴HCl produced will be 1 mole and Hydrogen of 0.5 mole will remain unreacted
Answer : (a)