gneet

Study Companion

For more NEET and AIIMS mcq on Chemical arithmetic and volumetric analysis Visit www.gneet.com
Question Q137) Specific volume of cylindrical virus particle is 6.02 × 10-2 cc/gm whose radius and length are 7 Å and 10 Å respectively. If NA= 6.02 ×1023, find molecular weight of virus.



SOLUTION

1 Å = 10-10 m
Volume of virus = πr2h
= π ×(7×10-10)2× 10×-10 cc
= 1.54×10-27 m3
6.02× 10-2 cc = 1 g
Or 6.02 × 10-8 m3 = 10-3 kg
∴ weight of 1.54 × 10-27 m- = w


W is the weight of one virus
∴molecular weight M of virus = w ×NA

Answer : (a)