gneet

Question
Q152) Volume occupied by one molecule of water (density = 1 g cm^{–3}) is …

SOLUTION

Mass of one mole of water or molecular mass =18g

As volume = mass/density

∴ Volume of 1 mole of water = 18 ml

One mole contains 6.023× 10^{–23} number of molecules

∴ Volume of one molecule of water =

18/(6.023×10^{23} )=3×10^{-23} ml
As 1ml = 1cm^{3}
∴ Volume occupy by one molecule of water = 3.0 × 10^{–23} cm^{3}
Answer : (d)