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Question Q157) How many grams of CH3OH should be added to water to prepare 150 ml solution of 2 M CH3OH?



SOLUTION

Molecular weight of CH3OH = 12+4+16 = 32g
M=(Wt of solvant×1000)/(Molar wt×volume of olution in mL)
2=(w×1000)/(32×150)
W= 9.6 g
Answer: (c)