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QUESTION
Q26) If 0.5 mol of BaCl2 is mixed with 0.2 mol of Na3PO4, the maximum number of moles of Ba3(PO4)2 that can be formed is ... [ IIT 1981]




SOLUTION

3BaCl2 + 2Na3PO4 → Ba3(PO4)2
Limiting reagent is Na3PO4
0.2 mol Na3PO4 wil give Ba3(PO4)2
=½ × 0.2=0.1 molAnswer: (d)