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Q54) What quantity of ammonium sulphate is necessary for the production of NH3 gas sufficient to neutralize a solution containing 292g of HCl ? [ HCl \ 36.5 , (NH4)2SO4=132; NH3=17] .. [ CPMT 1992]


NH4)2SO4 will produce two moles of NH3 wil neutralize 2 moles of HCl
Thus 132 g NH4)2SO4=2(36.5) o HCl=73 g of HCl
Thus for 292 g HCl=528 g of NH4)2SO4 Answer: (c)