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QUESTION
Q79) The total number of protons in 10g of calcium carbonate is ( NA=6.023×1023)




SOLUTION

molecular wt of CaCO3=100 g
∴ 10g=0.1 mole=6.02 ×1022 molecules
Now one molecule of CaCO3=20+6 +3×8=50
∴ Number of protons=50×6.02 ×1022=3.010×1024
Answer: (c)